Login Issue - Php / MySQL
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Description
Experience Level: Expert
Estimated project duration: 1 day or less
Hi there,
I took a bunch of fields and associated form checkers off my online form. I can fill in the form and submit it and all is well.
The issue is when I login to update my information. Instead of getting to view and update the info, I get a link to "complete the signup process" - (which I have already done).
So anyone looking to update this information at the moment has to re-register everything.
I think the form is checking for information that is no longer submitted. I think that this piece of code (below) needs to be modified as the "contact phone" is no longer submitted, but I could be wrong and the error may be elsewhere - there are a few pages of php code:
------------------------------------------
// check jobseeker is registered
$sql = db_query("SELECT id, contactphone FROM candidates WHERE email = '{$FORM['email']}' AND password = '{$FORM['password']}' LIMIT 1");
$num_rows = db_num_rows($sql);
if ($sql && $num_rows == 1) {
$JOBSEEKER = db_fetch_array($sql);
if ($JOBSEEKER['contactphone'] != '') {
____________________________________
As I'm not sure how long a fix will take, so I've put in an hourly rate (below).
Thank you for your help.
Robert
I took a bunch of fields and associated form checkers off my online form. I can fill in the form and submit it and all is well.
The issue is when I login to update my information. Instead of getting to view and update the info, I get a link to "complete the signup process" - (which I have already done).
So anyone looking to update this information at the moment has to re-register everything.
I think the form is checking for information that is no longer submitted. I think that this piece of code (below) needs to be modified as the "contact phone" is no longer submitted, but I could be wrong and the error may be elsewhere - there are a few pages of php code:
------------------------------------------
// check jobseeker is registered
$sql = db_query("SELECT id, contactphone FROM candidates WHERE email = '{$FORM['email']}' AND password = '{$FORM['password']}' LIMIT 1");
$num_rows = db_num_rows($sql);
if ($sql && $num_rows == 1) {
$JOBSEEKER = db_fetch_array($sql);
if ($JOBSEEKER['contactphone'] != '') {
____________________________________
As I'm not sure how long a fix will take, so I've put in an hourly rate (below).
Thank you for your help.
Robert
Robert O.
100% (57)Projects Completed
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