
Advanced PHP and MySQL Form for Joomla (breezing / facile forms intergration)
5682
£40/hr(approx. $54/hr)
- Posted:
- Proposals: 7
- Remote
- #28441
- Archived
Description
Experience Level: Expert
Hi
I urgently (within next two days!) need someone to implement a form on a 1.5 Joomla instance using breezing forms. All the fields and unique names have been set up in the front end ready. The front end needs a cloneTrue script so the user can add extra rooms and this is done with CSS already have this already. The bit I can't do is how to implement a simple calculation resulting in a value shown in the backend field which is the "heat requirement" (a hidden field?). The formula for calculating the "heat requirement" is Heat Requirement = Room Vol x Heat Loss Factor x Temperature Difference all divided by 2800.
Notes:
1. Temperature Differences:
Lounge, Dining Room, Study, Kitchen, Hallway & Conservatory would generate a Temp. Differerence of 27.5Â’ºC in Location 1, 30Â’ºC in Location 2 and 32.5Â’ºC in Location 3
Other rooms would be 2.5Â’ºC less per location
2. Heat Loss Factors HLF ( based on sheltered location)
Insulation Standard:
Poor= HLF 5 except for conservatory, which would have 6
Average= HLF 4.5
Good = HLF 4
If Location exposed then 0.5 to be added to HLFs.
If the project is done within 24 hrs a bonus of £50 will be paid ontop of fee. Any questions get in touch.
I urgently (within next two days!) need someone to implement a form on a 1.5 Joomla instance using breezing forms. All the fields and unique names have been set up in the front end ready. The front end needs a cloneTrue script so the user can add extra rooms and this is done with CSS already have this already. The bit I can't do is how to implement a simple calculation resulting in a value shown in the backend field which is the "heat requirement" (a hidden field?). The formula for calculating the "heat requirement" is Heat Requirement = Room Vol x Heat Loss Factor x Temperature Difference all divided by 2800.
Notes:
1. Temperature Differences:
Lounge, Dining Room, Study, Kitchen, Hallway & Conservatory would generate a Temp. Differerence of 27.5Â’ºC in Location 1, 30Â’ºC in Location 2 and 32.5Â’ºC in Location 3
Other rooms would be 2.5Â’ºC less per location
2. Heat Loss Factors HLF ( based on sheltered location)
Insulation Standard:
Poor= HLF 5 except for conservatory, which would have 6
Average= HLF 4.5
Good = HLF 4
If Location exposed then 0.5 to be added to HLFs.
If the project is done within 24 hrs a bonus of £50 will be paid ontop of fee. Any questions get in touch.
Deb O.
0% (0)Projects Completed
1
Freelancers worked with
2
Projects awarded
100%
Last project
6 Oct 2010
United Kingdom
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